In a maize coloured endosperm (C) is dominant over colourless (c) and full endosperm (R) is...
In a maize coloured endosperm (C) is dominant over colourless (c) and full endosperm (R) is dominant over shrunken (r). When a dihybrid of F1 generation was test crossed, it produced four phenotypes in the following %:
1. Coloured and full - 45%
2. coloured and shrunken - 5%
3. Colourless - Full - 4%
4. Colourless - shrunken - 46%
From these data what would be distance between the two non allelic genes?
Homework Answers
Representation:
Trait 1- Endosperm color:
- Colored = C = dominant, genotype= CC/Cc
- Colorless = c= recessive, genotype= cc
Trait 2- Endosperm Type:
- Full= R = dominant, genotype= RR/Rr
- Shrunken = r= recessive, genotype= rr
CCRR x ccrr
F1: CcRr
- Test cros:
Cross: CcRr x ccrr
For CcRr- gcmetes= CR, cr, Cr, cR
For ccrr-gcmetes = cr
|
cr |
cr |
|
|
CR |
CcRr |
CcRr |
|
Cr |
Ccrr |
Ccrr |
|
cR |
ccRr |
ccRr |
|
cr |
ccrr |
ccrr |
For independent assortment: ratio= 1:1:1:1
Recombinants =Colored-shrunken =5 % and Colorless-full = 4% =9%
Parental = Colored-full = 45% and Colorless-shrunken =46% =45+46= 91%
Total =100
RF= 9/100 x 100 = 9%
Distance = 9 MU
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