Question

Experiment 9-Post-lab Questions 1. Methanol (CH,OH) can be produced by the reaction of carbon monoxide (CO) with hydrogen (H,). The balanced chemical reaction is: cO@)+2 H, (g)CH,OH() Suppose 14.0 g of carbon monoxide is reacted with 8.0 g of hydrogen. a. Which reactant is the limiting reagent? b. What is the theoretical yield for methanol? c. At the completion of the reaction, how many grams of the excess reagent will remain? 2. Iron(III) oxide (Fe,O,) can be converted to iron metal (Fe) by the reaction with carbon (C) where the other product is carbon dioxide (CO,). The balanced chemical reaction is: 2 Fe, O, (s)+3 C(s) 4 Fe(s)+3 CO, (g) Suppose 3 moles of iron(II) oxide is reacted, a. How many moles of carbon are needed to react exactly with the iron oxide with no amount of either reactant left over? b. How many moles of iron will be produced? c. How many moles of carbon dioxide will be produced? 109

Answer 1

01 Reactimis- cog9) +2H2(g) → CH2OH(). (a). I4gm Carbon monoxide. to a gm Cambon monuyerde HA 9 (12+16) gm mole => 0.5 moles Carbon monoxide. 8 gm. Hy & ½ mole. Ha + A mole Hz. So, Cambon monoxide is the limiting reagent in this reaction. D as it decides the amount of product (CH20H). (b). From the reaction Lequivalent. co gives Lequivalent CH3OH. So, 0,5 molex. co will give 0.5 moles CH3OH. 0.5 moles CH, OH = 0.5% (12+3+16+1) Gm CHzott. 16 gm CH2OH Si, The gretical yield y 16gm. From the reaction it is clear that 1 equivalent co will reget lequivalent of Hy Accordingly, 0.5 moles co. will react I moles of. Hz. Rest (4-1) =3 moles are excus. 3 moles thy 3x2=69m 12. So, excers Hy is 69m!' CC). 021. 2 F2,03Cs) + 3G (8) + 4 Fe (s) +300269) 3 moles of imm (111) gyerde (Fe,03) is reacted. (8) From the reaction 2 moley Re, og react with 8 moles of Camboy . Then I mous of Feza will react with 3²x3 moles = % molesot Coorbon 72 Caribe - 4.5 moles of coothim

From the reaction it is clear that Requivalent te, og will give. 4 equiratent Fe. So, z moles of regoz will give & moles Fe. Anus! E moles. From the reaction. Lequivalent Feren will give. Bequivalent 202 So, 3 moles of Fey03 will give. 34*3 moles = 4.5 moles cez Ans: 4.5 moles