Question

In C Langage

Write a grading program for a class with the following grading policies:-

a. There are two quizzes, each graded on the basis of 10 points.

b. There is one midterm exam and one final exam, each graded on the basis of 100

points.

c. The final exam counts for 50 percent of the grade, the midterm counts for 25 percent

and the two quizzes together count for a total of 25 percent.

Grading system is as follows:-

>90 A

>=80 and <90 B

>=70 and <80 C

>=60 and <70 D

<60 E

The program should read in the student's scores and output the student's record, which

consists of two quiz and two exam scores as well as the student's average numeric

score for the entire course and the final letter grade. Define and use a

structure

for the

student record.

Utilize these function prototypes:-

void input(StudentRecord * student);

//should prompt for input for one student and

set the structure variable members.

void computeGrade(StudentRecord * student);

//use this to calculate the numeric

average and letter grade.

void output(const StudentRecord student);

//outputs the student record.

Sample Output

:-

Sample data for the test run:-

1 7 10 90 95

2 9 8 90 80

3 7 8 70 80

4 5 8 50 70

5 4 0 40 35

Output:

enter the student number:

1

enter two 10 point quizes

7 10

enter the midterm and final exam grades. These are 100 point tests

90 95

enter the student number:

2

enter two 10 point quizes

9 8

enter the midterm and final exam grades. These are 100 point tests

90 80

enter the student number:

3

enter two 10 point quizes

7 8

enter the midterm and final exam grades. These are 100 point tests

70 80

enter the student number:

4

enter two 10 point quizes

5 8

enter the midterm and final exam grades. These are 100 point tests

50 70

enter the student number:

5

enter two 10 point quizes

4 0

enter the midterm and final exam grades. These are 100 point tests

40 35

The record for student number: 1

The quiz grades are: 7 10

The midterm and exam grades are: 90 95

The numeric average is: 91.25

and the letter grade assigned is A

The record for student number: 2

The quiz grades are: 9 8

The midterm and exam grades are: 90 80

The numeric average is: 83.75

and the letter grade assigned is B

The record for student number: 3

The quiz grades are: 7 8

The midterm and exam grades are: 70 80

The numeric average is: 76.25

and the letter grade assigned is C

The record for student number: 4

The quiz grades are: 5 8

The midterm and exam grades are: 50 70

The numeric average is: 63.75

and the letter grade assigned is D

The record for student number: 5

The quiz grades are: 4 0

The midterm and exam grades are: 40 35

The numeric average is: 32.5

and the letter grade assigned is F

Answer 1

Please find below the complete code as per the requirements. It is well explained inside the code using comments.

#include <stdio.h>

// StudentRecord Structure
struct StudentRecord
{
   int studentNo;           // student no.
   int quiz1Score;           // score of quiz 1
   int quiz2Score;           // score of quiz 2
   int midtermScore;       // score of exam 1
   int finalExamScore;       // score of exam 2
   float avgNumericScore;   // average numeric score
   char letterGrade;       // letter grade
};

// prompt for input for one student and set the structure variable members.
void input(struct StudentRecord *student);

// calculates the numeric average and letter grade.
void computeGrade(struct StudentRecord *student);

// outputs the student record.
void output(const struct StudentRecord student);

// main function
int main()
{
   int i;

   // array of StudentRecord
   struct StudentRecord record[5];

   // read student information
   for (i = 0; i < 5; i++)
   {
       input(&record[i]);
   }

   // compute grades
   for (i = 0; i < 5; i++)
   {
       computeGrade(&record[i]);
   }

   // print the output
   for (i = 0; i < 5; i++)
   {
       output(record[i]);
   }

   return 0;
}

// prompt for input for one student and set the structure variable members.
void input(struct StudentRecord *student)
{
   // read and input student record
   printf("Enter the student number:\n");
   scanf("%d", &student->studentNo);
   printf("Enter two 10 point quizes:\n");
   scanf("%d %d", &student->quiz1Score , &student->quiz2Score);
   printf("Enter the midterm and final exam grades. These are 100 point tests:\n");
   scanf("%d %d", &student->midtermScore, &student->finalExamScore);
}

// calculates the numeric average and letter grade.
void computeGrade(struct StudentRecord *student)
{
   int sumQuizzes;           // sum of quizzes
   sumQuizzes = student->quiz1Score + student->quiz2Score;

   // calculate average numeric score
   student->avgNumericScore = ((float)sumQuizzes * 25 / 20) + ((float)(student->midtermScore) * 25 / 100) + ((float)(student->finalExamScore) * 50 / 100);

   // find numeric grade
   if (student->avgNumericScore > 90)
       student->letterGrade = 'A';
   else if (student->avgNumericScore >= 80)
       student->letterGrade = 'B';
   else if (student->avgNumericScore >= 70)
       student->letterGrade = 'C';
   else if (student->avgNumericScore >= 60)
       student->letterGrade = 'D';
   else
       student->letterGrade = 'E';
}

// outputs the student record.
void output(const struct StudentRecord student)
{
   printf("The record for student number: %d\n", student.studentNo);
   printf("The quiz grades are: %d %d\n", student.quiz1Score, student.quiz2Score);
   printf("The midterm and exam grades are: %d %d\n", student.midtermScore, student.finalExamScore);
   printf("The numeric average is: %.2f\n", student.avgNumericScore);
   printf("and the letter grade assigned is %c\n", student.letterGrade);
}

Below is the sample output:

Enter the student number: Enter two 10 point quizes: 7 10 Enter the midterm and final exam grades. These are 100 point tests: 90 95 Enter the student number: 2 Enter two 10 point quizes: 9 8 Enter the midterm and final exam grades. These are 100 point tests: 90 80 Enter the student number: 3 Enter two 10 point quizes: 7 8 Enter the midterm and final exam qrades. These are 100 point tests: 70 80 Enter the student number: 4 Enter two 10 point quizes: 5 8 Enter the midterm and final exam grades. 50 70 Enter the student number: These are 100 point tests: Enter two 10 point quizes: 4 Enter the midterm and final exam grades. 40 35 The record for student number: 1 The quizgrades are: 7 10 The midterm and exam grades are: The numeric average is: 91.25 and the letter grade assigned is A The record for student number 2 The quizgrades are: 9 8 The midtern and exam grades are: 90 80 The numeric average is: 83.75 and the letter grade assigned is B The record for student number: 3 The quiz grades are: The midtern and exam grades are: 70 80 The numeric average is: 76.25 and the letter grade assigned is C The record for student number: 4 The quizgrades are: 5 8 The midterm and exam grades are: 50 70 The numeric average is: 63.75 and the letter grade assigned is D The record for student number: 5 The quizgrades are: 40 The midtern and exam grades are: 40 35 The numeric average is: 32.50 and the letter grade assigned is E These are 100 point tests: 90 95 7 8

This completes the requirement. Let me know if you have any queries.

Thanks!