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A 10-cm-long thin glass rod uniformly charged to 15.0 nC and a 10-cm-long thin plastic rod...

A 10-cm-long thin glass rod uniformly charged to 15.0 nC and a 10-cm-long thin plastic rod uniformly charged to - 15.0 nC are placed side by side, 3.80 cm apart. What are the electric field strengths E1 to E3 at distances 1.0 cm, 2.0 cm, and 3.0 cm from the glass rod along the line connecting the midpoints of the two rods? Specify the electric field strength E1 Specify the electric field strength E2 Specify the electric field strength E3

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Answer #1

An. To get the field strength at the distances due to the rods, we use the expression of the field at a point on the bisector of a rod. Since the field at each point on the line joining their midpoints due to each rod is to the right, so to get the total field strength we add the field due to each rod.

The electric field the distances /.ocm due to both aodsPonts fo the iaht Ieky彳 he net field d eack pont* e rods ER due to fheAght Aod (plastic ) EL- due to the Jeft hod (3lass) The dedric feld at point on the bisecfor of a charged hod is given b The mag-clude 1.27haf the rod andx-distance e point f the od 6jn Yom So we have lods af fhe length= locm:0.1m field due fo the rght fodd ferd rength due to theSo strength of the field dlue to tuo rodls » Ekla) 2 リ 5 rod So 266x10 em from the sfs o cm rom the aless rod at 2.o1312 2- om he glass rod.

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