Question

A 10-cm-long thin glass rod uniformly charged to 7.00 nC and a 10-cm-long thin plastic rod uniformly charged to - 7.00 nC are placed side by side, 3.70 cm apart. What are the electric field strengths E1 to E3 at distances 1.0 cm, 2.0 cm, and 3.0 cm from the glass rod along the line connecting the midpoints of the two rods?

Answer 1

Net electric field due to the charged rod at the centre is given by, 2 Electric field E is given by, 10x102 m 2 (0.01m) (0.01m)+ ((3.7-1)x102) 37-1)x102) m) -1.23x103 NIC+4.10x101 N/C =(1.23×105)-(410x104) -164000 N/C Therefore, the electric field strength Elis l64000 NCI

Electric field E2 is given by, 2(10x102 m (0.02 m) , (0.02m)+ (87-2) 10) m4(8.7-2)-10*) m0- 3.7-2) x 10 m+ - 58494 N/C +75003 N/C 133497.40 N/C Therefore, the electric field strength E, is 98 105 N/C Electric field E3 is given by, (0.03 m), (0.03 m) + 003m-(0*10*m) 2 9x10 N.m7x10 2 (10x10* m) 3.7-3) × 10-2 3.7-3x10%) m) + 36014.7 N/C +10462.3 N/C -140636 N/C Therefore, the electric field strength E^ is 140636 N/C