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Two skaters gliding on ice run into each other head-on. If the two skaters hold onto each other and continue to move as a unit after the collision


Part III: Solve the following problems 


Two skaters gliding on ice run into each other head-on. If the two skaters hold onto each other and continue to move as a unit after the collision, what will be their resultant velocity? Skater A has a velocity of 5 m/s and a mass of 65 kg. Skater B has a velocity of 6 m/s and a mass of 60 kg.

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Answer #1

For Skater A,

mass = ma = 65 kg

velocity = ua = 5 m/s

For Skater B,

mass = mb = 60 kg

velocity = ub = 6 m/s

now assume final velocity = vf

so conservation of momentum

ma * ua + mb * ub = ( ma + mb ) * vf

65 * 5 + 60 * 6 = ( 65 + 60 ) * vf

vf = 5.48 m/s <<<<<<< ANSWER

feel free to drop comment if you have any doubt.

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