Question

two wires are tied to the 300g sphere

Two wires are tied to the 300 g sphereshown in Figure CP7.61. The sphere revolves in a hori­zontalcircle at a constant speed of 9.0 m/s.What is the tension in each ofthe wires?
T1 =
N (top wire)
T2 = N (bottom wire)


0 0
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Answer #1

sin theta = 0.5/1 = 0.5

theta = 30 with the horizantal

r = L*cos30 = 1*cos30 = 0.866 m

along horizantal


Tu*cos30 + Tl*cos30 = m*v^2/r

Tu*cos30 + Tl*cos30 = (0.3*6.8*6.8)/0.866 = 16.01


Tu*cos30 + Tl*cos30 = 16.01


Tu + Tl = 18.48 ..................(1)


along vertical

Tu*sin30 = mg + Tl*sin30


Tu = 2mg+Tl = (2*0.3*9.8)+Ti


Tu - Tl = 5.88 ..............(2)

from 1 &2


Tu = 12.18 N      <-----------answer

Tl = 6.30 N <-----------answer

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Answer #3

Label upper wire Tension = T1 and lower wire Tension = T2

Now show and label the X & Y COMPONENTS of T1 & T2

From the correctly drawn components see that the EQUILIBRIUM equations are:

?Fy=0: T2(sin 30

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