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Question 1 (3 points) The figure shows two wires tied to a 3.7 kg sphere that revolves in a horizontal circle at constant spe
1:00:00 Time Left:0:58:25 1.0 m 600 50 N 36 N 25 N 27 N Previous Page Next Page Page 1 of 15
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Answer #1

Consider the tension in each string is T.

When you draw the free body diagram of the sphere, the weight of sphere mg acts downwards and T acts along each string

The net acceleration of the sphere is towards the center (centripetal acceleration).

So there is no vertical acceleration.
Thus
mg = Tcos60 + Tsin60

T = mg/(cos60 + sin60)

   = 3.7*9.81/(cos60 + sin60)
T = 26.57 N

Therefore, the closest option is fourth option is correct.

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