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Q1 = 6.0 nC is at (0.30 m, 0); Q2 = -1.0 nC is at (0,...

Q1 = 6.0 nC is at (0.30 m, 0); Q2 = -1.0 nC is at (0, 0.10 m); Q3 = 5.0 nC is at (0, 0). What is the y-component of the net force on the 5.0 nC charge?

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Answer #1

Y component of the force on Q3 will be only due to Q2

therefore

F23 = k Q1Q3 / R^2

R = 0.1m

substituting values we get

F23 = 0.0000045 N

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