Chapter 30, Problem 031
If 67.5 cm of copper wire (diameter = 0.894 mm, resistivity = 1.69 x 10-892-m) is formed into a circular loop and placed perpendicular to a uniform magnetic field that is increasing at the constant rate of 14.5 mT/s, at what rate is thermal energy generated in the loop?
If 67.5 cm of copper wire (diameter = 0.894 mm, resistivity = 1.69 x 10-892-m) is formed into a circular loop
If 66.4 cm of copper wire (diameter = 1.08 mm, resistivity = 1.69 10-82.m) is formed into a circular loop and placed perpendicular to a uniform magnetic field that is increasing at the constant rate of 12.5 mT/s, at what rate is thermal energy generated in the loop? Number Units the tolerance is +/-2%
If 54.4 cm of copper wire (diameter = 0.869 mm, resistivity = 1.69 × 10-8Ω·m) is formed into a circular loop and placed perpendicular to a uniform magnetic field that is increasing at the constant rate of 9.52 mT/s, at what rate is thermal energy generated in the loop?
A 22.0-cm-diameter coil consists of 30 turns of circular copper wire 2.8 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 9.35×10−3 T/s . The resistivity of copper is 1.68×10−8Ω⋅m. Determine the current in the loop. Determine the rate at which thermal energy is produced.
A length of 20-gauge copper wire (of diameter 0.8118 mm) is formed into a circular loop with a radius of 26.0 cm. A magnetic field perpendicular to the plane of the loop increases from zero to 18.0 mT in 0.24 s. Find the average electrical power dissipated in the process.
A length of 20-gauge copper wire (of diameter 0.8118 mm) is formed into a circular loop with a radius of 21.0 cm. A magnetic field perpendicular to the plane of the loop increases from zero to 12.0 mT in 0.22 s. Find the average electrical power dissipated in the process.
A length of 20-gauge copper wire (of diameter 0.8118 mm) is formed into a circular loop with a radius of 23.0 cm. A magnetic field perpendicular to the plane of the loop increases from zero to 10.0 mT in 0.22 s. Find the average electrical power dissipated in the process.
A length of 20-gauge copper wire (of diameter 0.8118 mm) is formed into a circular loop with a radius of 26.0 cm. A magnetic field perpendicular to the plane of the loop increases from zero to 11.0 mT in 0.26 s. Find the average electrical power dissipated in the process. answer in W
A 24.0-cm diameter coil consists of 45 turns of circular copper wire 3.0 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 7.85×10−3 T/s . The resistivity of copper is 1.68×10−8Ω⋅m. Determine the current in the loop. (Express your answer to two significant figures and include the appropriate units.) Determine the rate at which thermal energy is produced. (Express your answer to two significant figures and include the appropriate units.)
A 24.0-cm diameter coil consists of 45 turns of circular copper wire 3.0 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 7.85×10−3 T/s .The resistivity of copper is 1.68×10−8Ω⋅m. a) Determine the current in the loop. (Express your answer to two significant figures and include the appropriate units.) b) Determine the rate at which thermal energy is produced.(Express your answer to two significant figures and include the appropriate units)
A 20.8 cm -diameter coil consists of 30 turns of circular copper wire 2.4 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 7.64×10−3 T/s . PART A: Determine the current in the loop. PART B: Determine the rate at which thermal energy is produced.