Question

Draw a free-body diagram for a car (assume that it is moving from left to the right).

Draw the force vectors with their tails at the dot. The orientation of your vectors will be graded. The exact length of your vectors will not be graded but the relative length of one to the other will be graded.  

Answer 1

I do assume you are not driving up or down a hill, which will be a more complicated diagram, involving incline angles and misaligned forces.

Normal force (N) acts upward on the car
Weight (W) acts downward on the car
Air drag (D) acts to the reverse on the car
The road traction force (F) acts forward on the car.

I changed the name of F because it isn't the "force of the engine". that propels the car forward. The engine transmits power to the driving wheels, which apply a reverse direction force on the road. The road then exerts an equal and opposite force on the car, as per Newton's 3rd law. I got this wrong on an exam in high school, calling it the "force from the engine".

Be sure to draw your diagram, such that N and W are equal in magnitude since the car should not be sinking into the asphalt.

Due to your information about the car speeding up, draw your diagram, such that F is larger than D. If they were equal, the car would be moving at a constant velocity. If D were greater and/or if F had a backward direction instead; then the car would be slowing down.

2)

Now increase the tension vector lengthier than the weight downward vector.
This gives an upward acceleration to the package.

T > mg.