Using Kirchhoff's Laws, find the currents I1, I2, and I3 in the circuit shown. Hint: Use both junction rule and voltage rule from the two loops.
let us first name the loops . let the upper loop be loop 1, lower one be loop2 and a third loop which is the whole circuit except the middle line connections.
kirchoffs voltage law for loop 1
14-4(I1-I3)+10 -6I1=0
kirchoffs voltage law for loop 2
-10 +2I3+6I1=0
kirchoffs voltage law for loop 3
14-4(I1-I3)+2I3=0
solving these three equations we get
I1= 2A
I2= 1A
I3=-1A
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