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Image for Consider the circuit shown in the figure below. Calculate the currents I1, I2, and I3.

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Answer #1

applying KVL on upper loop

24 - 2 * I1 - 4 * I1 - 3 * I3 = 0

applying KVL on lower loop

12 + 3 * I3 - I2 - 5 * I2 = 0

applying KVL on outer loop

24 - 2 * I1 - 4 * I1 - I2 - 5 * I2 + 12 = 0

on solving these equations we get

I1 = 3 A

I2 = 3 A

I3 = 2 A

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