Question

Sketch the graph of the superball's velocity vs. time, , from the instant it is dropped () until...

Sketch the graph of the superball's velocity vs. time, , from the instant it is dropped () until it bounces to its maximum height (). Assume that the superballundergoes an elastic collision with the scale, and that the scale's recoil velocity is negligible. The light colored graph already present in the answer window is .
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Answer #2

The set of coordinates for clay are (0,0).(2.9 s,-28 m/s). (3.1 s,0).(6 s,0) Hence, the duration of collision is, t 3.1 s-2.9 s 0.2 s The clay and the super ball are dropped. Hence, the first set of coordinates for the ball is (0,0) Both the clay and the superball hit the scale 2.9 s after they are dropped. Hence, the second set of coordinates is (2.9 s,-28 m/s) The duration of collision is same for both the clay and the super ball. Thus, the time coordinate is 3.1 s. By the law of conservation of momentum, the momentum at the second coordinate must be equal to that at the third coordinate. Thus, the velocity is negative here because the direction of velocity is opposite to that of the initial velocity v 28 m/s Thus, the third coordinate is (3.1 s, 28 m/s) At maximum height the velocity is zero. The ball reaches the maximum height at t = 6 s Hence the fourth set of coordinates is (6 s,0 Hence, the graph passes through the points (0,0).(2.9 s,-28 m/s). (3.1 s, 28 m/s). (6 s,0) as shown below 40 30 20 10 1.0 2.0 3b 4.0 5.0 6.0 10 20 30 40

The change in velocity during collision of the clay is, (0-(-28 m/s)) 28 m/s The change in velocity during collision of the s

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Answer #1

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the change in velocity of the ball is greater ( double) that of the clay.

at t=3 sec. The ball velocity is 0. but the clay velocity hasnt come to zero yet. It is around -15m/s.

So the force exerted on the ball is greater. (according to the graph)

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