A 75 kg person is standing on a scale in an elevator. What is the reading...

Question

Question

A 75 kg person is standing on a scale in an elevator. What is the reading of the scale in newtons if the elevator is

a) at rest
b) moving up at a constant velocity of 2.00 m/s
c) accelerating up at 2.00 m/s

Answer 1

Answer #1

a) W = mg = 75*9.8 = 735 N

b) It is moving with constant velocity so no acceleration is acting on elevator

So weight is still the same assuming elevator at rest

W = mg = 75*9.8 = 735 N

c) When the elevator is accelerating up

N - mg = ma

Where N is the normal /weight of the person

N = m(g+a)

N = 75 (9.8+2)

N = 75*11.8 =885 N

Answer 2

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