A fan blade, initially at rest, rotates with a constant acceleration of 0.025 rad/s2. What
A fan blade starts at rest and begins moving with a constant angular acceleration of 2.00 rad/s2. The blade rotates through an angle of 285 radians in an 11.0 s interval that did not start at t = 0s. How long did it take the blade to reach the beginning of the 11.0-s interval? Answer must be in seconds.
A fan blade is rotating with a constant angular acceleration of +8.5 rad/s2. At what point on the blade, as measured from the axis of rotation, does the magnitude of the tangential acceleration equal that of the acceleration due to gravity?
A wheel (radius = 0.20 m) starts from rest and rotates with a constant angular acceleration of 2.0 rad/s2. At the instant when the angular velocity is equal to 1.2 rad/s, what is the magnitude of the total linear acceleration (in m/s2) of a point on the rim of the wheel? 0.29 0.4 0.49 0.69
A wheel, starting from rest, rotates with a constant angular acceleration of 4.50 rad/s2. During a certain 5.00 s interval, it turns through 85.0 rad. (a) What is the angular velocity of the wheel at the start of the 5.00 s interval? rad/s (b) How long has the wheel been turning before the start of the 5.00 s interval? s
A wheel, starting from rest, rotates with a constant angular acceleration of 1.70 rad/s2. During a certain 3.00 s interval, it turns through 16.1 rad. (a) How long had the wheel been turning before the start of the 3.00 s interval? (b) What was the angular velocity of the wheel at the start of the 3.00 s interval?
A wheel of diameter 50.0 cm starts from rest and rotates with a constant angular acceleration of 5.00 rad/s2. At the instant the wheel has completed its second revolution, compute the radial acceleration of a point on the rim in two ways. Using the relationship arad = ω2r. From the relationship arad = v2/r.
A wheel of diameter 30.0 cm starts from rest and rotates with a constant angular acceleration of 2.50 rad/s2. At the instant the wheel has completed its second revolution, compute the radial acceleration of a point on the rim in two ways. Using the relationship arad = ω2r. From the relationship arad = v2/r.
A wheel rotates with a constant angular acceleration of 1.5π rad/s2. During a certain time interval its angular displacement is 3π rad. At the end of the interval its angular velocity is 5π rad/s. Its angular velocity at the beginning of the interval is: 4π rad/s zero 2π rad/s 9 rad/s 3π rad/s
Question 10 A wheel, starting from rest, rotates with a constant angular acceleration of 3.50 rad/s2. During a certain 6.00 s interval, it turns through 122 rad. (a) How long had the wheel been turning before the start of the 6.00 s interval? (b) What was the angular velocity of the wheel at the start of the 6.00 s interval? (a) Number Units (b) Number Units
A vertical wheel with a diameter of 50 cm starts from rest and rotates with a constant angular acceleration of 4 rad/s? around a fixed axis through its center counterclockwise. a. Where is the point that is initially at the bottom of the wheel at t = 5 s? Round your answer to one decimal place and express it as an angle in radians between 0 and 2π, relative to the positive x axis. b. What is the point's linear acceleration at...