Question

Two ice skaters, with masses of 50.0 kg and 85.0 kg, are at the center of a 30.0 m -diameter-circular rink



Two ice skaters, with masses of 50.0 kg and 85.0 kg, are at the center of a 30.0 m -diameter-circular rink. The skaters push off against each other and glide to opposite edges of the rink.

If the heavier skater reaches the edge in 10.0 s, how long does the lighter skater take to reach the edge?

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Answer #1

I set up a proportion with m1/m2= t1/twhich becomes 50/85 = t/10. I got an answer of 5.88s. MasteringPhysics said it was correct... though I'm sure there's another way to do it "using physics".

source: trial and error
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Answer #2
Total momentum is conserved. T
Σp before collision = Σp after
   0 = m1.v1 + m2.v2;
   m1.v1 = -m2.v2 ---------------(1)
The distance travelled by eack, d = R, radius of theRink.
      v =R/t
Eq (1) becomes,
              m1.R/t1 = m2.R/t2
Time, t1 = m1t2/m2 =50x10/85 = 5.88 s
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