Two ice skaters, with masses of 50.0kg and 65.0kg , are at the center of a 40.0m -diameter circular rink. The skaters push off against each other and glide to opposite edges of the rink.
If the heavier skater reaches the edge in 30.0s , how long does the lighter skater take to reach the edge?
Express your answer with the appropriate units.
For heavier skater ,
d =ut
u = 20 / 30 = 2/3 m/s
now for pushing using , momentum conservation
initial = final
0 = 50v + 65 x (2/3)
v = 0.867 m/s
t = d/v = 20 / 0.867 = 23.08 sec
Using momentum= mass x velocity and velocity = displacement /
time
You know that the heavier one takes 30 seconds to reach the side
and that he moves 20 metres to the side so you can use conservation
of momentum. ( I'm taking the heavier one's velocity to be positive
)
0 = (65 x 20/30) + (30 x -20/t) -------> 0 = 43.33 - 600/t
-------> 600/t = 43.33 ------> 600/43.33 = t
therefore t = 13.8568 seconds
Two ice skaters, with masses of 50.0kg and 65.0kg , are at the center of a...
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