In the coordinate system shown at right, particle l with charge q1 = q where q = 5.6 μC, is located at coordinates (-a, 0) m, where a=7.4 m

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In the coordinate system shown at right, particle l with charge q1 = q where q = 5.6 μC, is located at coordinates (-a, 0) m, where a=7.4 m

In the coordinate system shown at right, particle l with charge q1 = q where q = 5.6 μC, is located at coordinates (-a, 0) m, where a=7.4 m; particle 2 with charge q2 = 2q is located at coordinates (a, 0); particle 3 with charge q3=q is located at coordinates (0, a)

Part (a) Enter an expression for the electric potential at the origin, V0, using the given symbols

Part (b) Solve for the numerical value of V0 in volts

Part (c) Using to denote the direction of the electric field at the origin E0 measured counterclockwise from the positive x-axis, find tan(α).

Part (d) Now find sin(α).

Part (e) Calculate the value of a, in degrees between 0 and 360°.

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In the coordinate system shown at right, particle l with charge q1 = q where q = 5.6 μC, is located at coordinates (-a, 0) m, where a=7.4 m

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In the coordinate system shown at right, particle l with charge q1 = q where q = 5.6 μC, is located at coordinates (-a, 0) m, where a=7.4 m

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In the coordinate system shown at right, particle l with charge q1 = q where q = 5.6 μC, is located at coordinates (-a, 0) m, where a=7.4 m

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Add Answer to: In the coordinate system shown at right, particle l with charge q1 = q where q = 5.6 μC, is located at coordinates (-a, 0) m, where a=7.4 m

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In the coordinate system shown at right, particle l with charge q1 = q where q = 5.6 μC, is located at coordinates (-a, 0) m, where a=7.4 m