Question

      

Three charged metal disks are arranged as shown (cutaway view). The disks are held apart by insulating supports not shown in the diagram. Each disk has an area of 2.5 m² (this is the area of one flat surface of the disk). Use the value 8.85e-12 C²/(N·m²) for ?₀.The charge Q₁ = 5e-8 coulombs, and the charge Q₂ = 2e-7 coulombs.

What is the magnitude of the electric field in the region between disks 1 and 2? |₁₂| =________________V/m

What is the direction of the electric field between disks 1 and 2?2

+x

-x

+y

-y

+z

-z

Which of the following statements are true? Choose all that apply.

V_B - V_A = ^_((Q₁/2.5)/Epsilon Knot)*(0.003) volts

Along a path from A to B Delta

V_B - V_A = 0

To calculate V_C - V_B, which path should you choose?

A path starting at B and ending at C

A path starting at C and ending at B

It doesn't matter whether the path starts or ends at B

The sign of V_C - V_B should be:

Zero - no sign.

Negative, because Delta is in the same direction as  

Positive, because Delta is opposite to the direction of  

What is the potential difference V_C - V_B? V_C - V_B = ______________________________volts

What is the potential difference V_D - V_C? V_D - V_C =____________________ volts

What is the potential difference V_F - V_D? V_F - V_D =____________________ volts

What is the potential difference V_G - V_F?

V_G - V_F = ___________________ volts

What is the potential difference V_G - V_A?

V_G - V_A = _________________volts

The charged disks have tiny holes which allow a particle to pass through them. An electron which is traveling at a fast speed approaches the plates from the left side. It travels along a path from A to G. Since no external work is done on the system of plates + electron, DELTA K + DELTA U = W_ext = 0 Consider the following states: Initial, electron at location A. Final, electron at location G.

What is the change in potential energy of the system? DELTA U =_________________________________ joules

What is the change in kinetic energy of the electron? DELTA K =_________________________________ joules

Answer 1