a) VA - VB = -E1*dx1 + E2*dx2
= -725*0.4 + 425*0.2
= -205 V
b) VB - VA = -(VA - VB)
= 205 V
c) change in kinetic energy = Workdone
= q*delta_V
= -1.6*10^-19*(VB - VA)
= -1.6*10^-19*205
= -3.28*10^-17 J
d) minimum kinetic energy = -Workdone
= 3.28*10^-17 J
5. As shown in Figure 5.1, three large, thin, uniformly charged plates are arranged so that...
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