Unlike the idealized voltmeter, a real voltmeter has a resistance that is not infinitely large.
A voltmeter with resistance RV is connected across the terminals of a battery of emf E and internal resistance r. Find the potential difference Vmeter measured by the voltmeter.
What is Vmeter?
The concepts used to solve this problem are Kirchhoff’s loop rule and ohm’s law.
Initially, the current flowing through the circuit can be calculated by using the Kirchhoff’s loop rule.
Finally, potential difference of the voltmeter can be calculated by using the ohm’s law for the circuit.
Kirchhoff’s loop rule states that the sum of voltage across the all the circuit elements will be equal to zero.
The circuit diagram for the voltmeter is,
Applying the Kirchhoff’s loop rule, the equation will be,
Here, is the battery emf, is the current flowing through the circuit, is the voltmeter resistance, and is the internal resistance.
The expression for the potential difference of the voltmeter by applying Ohm’s law is,
Here, is the potential difference of the voltmeter.
According to the Kirchhoff’s loop rule, the equation will be,
Rewrite the above equation to find the current flow through the circuit.
The expression for the potential difference of the voltmeter is,
Substitute for .
Ans:The required potential difference measured by the voltmeter is .
Unlike the idealized voltmeter, a real voltmeter has a resistance that is not infinitely large. A...
When a battery voltage is measured by placing a high-resistance voltmeter across the terminals of the battery, the voltmeter reads 6.3V. With the voltmeter leads still attached, the battery terminals are then connected to a resistor in series with an ammeter. In this arrangement, the ammeter reads 150 mA, and the voltmeter reads 5.9V. What are the emf and the internal resistance of the battery?
A real battery is not just an emf. We can model a real 1.5 V battery as a 1.5 V emf in series with a resistor known as the "internal resistance", as shown in the figure(Figure 1) . A typical battery has 1.0 Ω internal resistance due to imperfections that limit current through the battery. When there's no current through the battery, and thus no voltage drop across the internal resistance, the potential difference between its terminals is 1.5 V,...
In the figure a voltmeter of resistance Rv = 480 s2 and an ammeter of resistance RA = 2.03 12 are being used to measure a resistance R in a circuit that also contains Ro = 100 1 and an ideal battery of emf ε = 12.0 V. Resistance R is given by Vli, where V is the potential across R and i is the ammeter reading. The voltmeter reading is V', which is V plus the potential difference across...
A battery with EMF 90.0 V has internal resistance Rb = 8.43 Ω .What is the reading Vv of a voltmeter having total resistance Rv = 475 Ω when it is placed across the terminals of the battery?What is the maximum value that the ratio Rb/Rv may have if the percent error in the reading of the EMF of a battery is not to exceed 5.00 % ?
A battery with EMF 90.0 V has internal resistance Rb = 9.93 A. What is the reading Vv of a voltmeter having total resistance Rv = 490 Ω when it is placed across the terminals of the battery? Express your answer with three significant figures. B. What is the maximum value that the ratio Rb/Rv may have if the percent error in the reading of the EMF of a battery is not to exceed 5.00 %? Express your answer with...
A battery with EMF 90.0 V has internal resistance Rb = 8.95 Ω . Part A What is the reading Vv of a voltmeter having total resistance Rv = 440 Ω when it is placed across the terminals of the battery? Vv = 88.2 V Part B What is the maximum value that the ratio Rb/Rv may have if the percent error in the reading of the EMF of a battery is not to exceed 5.00 % ? Express your...
For the circuit shown in the figure, both meters are idealized, the battery has no appreciable internal resistance, and the ammeter reads 1.45 A.a) What does the voltmeter read?b) What is the emf ε of the battery?
For the circuit shown in (Figure 1) both meters are idealized, the battery has no appreciable internal resistance, and the ammeter reads 1.40 A. Part A What does the voltmeter read?Part B What is the emf & of the battery?
A voltmeter is connected across the terminals of a 15.0 V battery and a 75 ohm appliances connected across its terminals. If the voltmeter reads 11.3 V How much power is dissipated by the appliance? What is the internal resistance of the battery?
For the circuit shown in the figure both meters are idealized, the battery has no appreciable internal resistance, and the ammeter reads 1.55 A.1.What does the voltmeter read?2.What is the emf ε of the battery?