Question

ans: PA=6,02%8 60 mm 1. Determine the rotation of the shaft end A for the torque loading shown. Section DC has an inner hole radius of 20 mm while AB and BC are solid. GBA = 27 gigapascals and Gps =39 gigapascals. T3 - 1600 Nm 36 mm TA = 800 Nm 250 mm 375 mm 400 mm

Answer 1

Given Dato : GAB= 27 GPO = 27X103 mpa GBP = 39 Apa - 39 2103 mpa dep= 20x2 = 40 mm 160ortim e s 800 soorten m 375mm 400mm i 250m Torque in shaft AB: Torque in shart BD, TAB = 800 nm = 800 x103 mm TBD = 800+1600 = 2400 Nm 2 =21009103 rumm of shaft polar moment of inestra (tol Tx364 ... (FPAB - 1 64.895 x103 mm 32 (FDec - 15.604 = 1272.345 x103 mmy

D ) = no exis 60f_co") = 1021.01 X10° normy 102.01 X10 since shafts are in series, OAD = OAB + OBC + OCD 1 TL TL TL - cena no t ( pm to the incon + GIP / AB GLp / BC G. Ip/co 800*1000 x 400 27x1000 x164.895x103) T [ 2400X1000X375 ( 39 x1000 X 1272-345x103) I 1:2400x1000x250 | 39x1000 x 1021.01x103 = 0.0718 + 0.0181 + 0.015 OAD - 0.1049 seed of shaft et end A The rotation is 0-1049 rad