In a galvanic cell, one half-cell consists of a lead strip dipped into a 1.00 M...

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In a galvanic cell, one half-cell consists of a lead strip dipped into a 1.00 M solution of Pb(NO). In the second half-cell,

X Uwe the References to access important values if needed for this question. The following standard reduction potentials have

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Answer 1

Answer #1

Question 1.

Part (a).

The half-reaction at the anode: Pb(s) ----> Pb²⁺(aq) + 2e^-

The half-reaction at the cathode: Ge⁴⁺(aq) + 4e- ----> Ge(s)

Part (b).

The standard electrode potential (E^o_cell) = (E^o_Ge⁴⁺/Ge) - (E^o_Pb2+/Pb)

i.e. 0.250 V = (E^o_Ge⁴⁺/Ge) - (-0.126 V)

i.e. E^o_Ge⁴⁺/Ge = 0.250 - 0.126 = 0.124 V

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Answer 2

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