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A Cacat Pb2+ Pb galvanic cell is constructed in which the standard cell voltage is 0.277 V Calculate the free energy change a

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0 Caeso + pbt2 cate of Pb (s) 1=2 AG = .. nF E cell F Faradays const almol = 964850332 OG = -2X 964850332 800277 Joule = -53oxidation ce + 3 lety 4ce t3 reduction - Ecetul cet3 Ecet ce = - 20340 - 1.760 Eceu co Cogo = - NF E cell] Ogoso disproportioo ago = RT INK = nF E cell Ink a -nf Ece [+= 25° C = 290k ] RT - 0.3 - - 3 x 9 6485.332 x 8.314 X 298 a. Ink = 350 04915 -35.

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