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Question 1 (6 marks) Part a) Find the following probabilities by checking the z table PC 1.5<Ζ-07) ii) P((1.15-Z 2.45) 0.35

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Answer #1

Solution,

Given that,

i ) P ( - 1.5 < Z < 0.7 )

P ( z < 0.7 ) - P ( z < - 1.5 )

Using standard normal table

= 0.7580 - 0.0668

= 0.6912

Probability = 06912

ii ) P ( 1.15 < Z < 2.45 )

P ( z < 2.45 ) - P ( z < 1.15 )

Using standard normal table

= 0.9929 - 0.8749

= 0.1180

Probability = 0.1180

iii ) Z0.35

P ( Z < Z ) = 0.35

Using standard normal table

z = - 0.39

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