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A 68 kg skier starts from rest at a height of H = 24 m above the end of the ski-jump ramp. As the skier leaves the ramp, his

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Answer #1

here,

let the velocity at the bottom of the track is v

Using conservation of energy

0.50 * m * v^2 = m * g * H

0.50 * v^2 = 9.8 * 24

v = 21.7 m/s

for the maximum height h

maximum height h = (v * sin(theta))^2/(2 * g)

maximum height h = (21.7 * sin(28))^2/(2 * 9.8)

maximum height h = 5.29 m

the maximum height is 5.29 m

part (b)

as the speed is independent of mass

the height remains the same

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