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For the diagram shown, =-10-pC = 6.2-pC = 0.55-m, and = 770, Find the electric force on due to the charge q1 magnitude 3.31 N a. b. 3.194.N 1.724 N d. 3.542.N 2.988.N 1.845_N C. directioin a. 293.3° b.295.8° c. 221.2 d. 245.1° 257°

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Answer #1

Solution:

5) Electric force (F) = k q1 *q2 / r^2

=> F = 9*10^9 * 10 *6.2 * 10^-13 / (0.55)^2

=> F = 1.845 N

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