Answer all question plz !!!!!!!!! with formula !!!!!!!!!!!!!!!!!!!!!!!!!!!!!
4)
A matrix will be singular when it's determinant is zero.
A)
4 |
0 | 1 |
19 | 1 | -3 |
7 | 1 | 0 |
Expanding along 1st row.
= 4*(1*0 - (-3)*1) - 0*(19*0 - 7*(-3)) + 1*(19*1 - 7*1)
= 12 + 0 + 12 = 24; Hence Non-singular
B)
4 | -2 | 1 |
-5 | 6 | 0 |
7 | 0 | 3 |
Expanding along 1st row
= 4*(6*3 - 0*0) -(-2)*( -5*3 -7*0) +1*(-5*0 - 6*7)
= 72 - 30 -42
=0; Hence Singular.
C)
7 | -1 | 0 |
1 | 1 | 4 |
13 | -3 | -4 |
Expanding along 1st row
= 7*(1*(-4) - 4*(-3)) - (-1)*(1*(-4) - 4*13) + 0*(1*(-3) - 1*13)
= 56 - 56 + 0
=0; Hence Singular
D)
-4 | 9 | 5 |
3 | 0 | 1 |
10 | 8 | 6 |
Expanding along 1st row
= (-4)(0*6 - 8*1) - 9*(6*3 -10*1) + 5*( 8*3 - 10*0)
= 32 -72 + 120
= 82 ; hence Non-singular
5)
A square matrix has rank n only if its determinant of order n is non-zero i.e. matrix of order n is non- singular.
From the above, we can see that A and D are a non-singular matrix and hence their rank is 3.
For B and C, we are sure that they has rank < 3 because they are the singular matrix of order 3.
Answer all question plz !!!!!!!!! with formula !!!!!!!!!!!!!!!!!!!!!!!!!!!!! 4. Test whether the following matrices are nonsingular:...
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