A diverging lens has a focal length of 65 cm. It is located 90
cm from an object.
a. Draw the ray tracing diagram to locate the image. Is the image
real or virtual?
b. Calculate the image location and the magnification for the
image. Compare your results with part a.
A diverging lens has a focal length of 65 cm. It is located 90 cm from...
A convex mirror has a focal length of 70 cm. An object is placed 40 cm from the mirror. a. Draw the ray tracing diagram to locate the image. Is the image real or virtual? b. Calculate the image location and the magnification for the image. Compare your results with part a.
A concave mirror has a focal length of 45 cm. An object is placed 35 cm from the mirror. a. Draw the ray tracing diagram to locate the image. Is the image real or virtual? b. Calculate the image location and the magnification for the image. Compare your results with part a. c. What would the image location and magnification be if the object were 55 cm from the mirror?
A 4.0 cm tall object is 5.0 cm in front of a diverging lens with a focal length of -6.0 cm. A converging lens with a focal length of 6.0 cm is located 8.0 cm behind the diverging lens. (As viewed from the side, from left to right, the sequence is object - diverging lens - converging lens - observer. Rays then travel from left to right through the system.) (a) Use ray tracing to draw image 1 and image...
A 20 cm tall object is located 70 cm away from a diverging lens that has a focal length of 20 cm. Use a scaled ray tracing to answer parts a-d. a. Is the image real or virtual? b. Is the image upright or inverted? c. How far from the lens is the image? d. What is the height of the image? e. Now use the thin lens equation to calculate the image distance and the magnification equation to determine...
A converging lens has a focal length of 7.5 cm. An object is placed 5 cm from the lens. a. Draw the rays tracing diagram to locate the image. Is the image real or virtual? b. Calculate the location and the magnification for this image.
An object is 15 cm in front of a diverging lens with a focal length of 10 cm. Part A Use ray tracing to determine the location of the image. Express your answer using two significant figures. q = Part B Is the image upright or inverted? Part C Is the image real or virtual?
Part A: A diverging lens has of focal length of 15.0 cm. An object is placed 21 cm to the left of the lens. a) draw a ray diagram showing the situation. b) find the location of the image produced by the lens (mind the signs). Part B: A converging lens is located 30 cm to the right of the previously mentioned diverging lens (part A). As a result, the image you found in part (a) is now instead located...
A converging lens with a focal length of 4.9 cm is located 20.9 cm to the left of a diverging lens having a focal length of -11.0 cm. If an object is located 9.9 cm to the left of the converging lens, locate and describe completely the final image formed by the diverging lens. a) Where is the image located as measured from the diverging lens? b) What is the magnification? c) Also determine, with respect to the original object...
A diverging lens has a focal length of magnitude 22.6 cm. (a) Locate the images for each of the following object distances. 45.2 cm distance cm location (behind or in front of lens) 22.6 cm distance cm location (behind or in front of lens) 11.3 cm distance cm location (behind or in front of lens) (b) Is the image for the object at distance 45.2 real or virtual? Is the image for the object at distance 22.6 real or virtual?...
A diverging lens has a focal length of magnitude 21.2 cm. (a) Locate the images for each of the following object distances. 42.4 cm distance cm location ---Select---in front of the lensbehind the lens 21.2 cm distance cm location ---Select---in front of the lensbehind the lens 10.6 cm distance cm location ---Select---in front of the lensbehind the lens (b) Is the image for the object at distance 42.4 real or virtual? real virtual Is...