Part A:
A diverging lens has of focal length of 15.0 cm. An object is placed 21 cm to the left of the lens.
a) draw a ray diagram showing the situation.
b) find the location of the image produced by the lens (mind the signs).
Part B: A converging lens is located 30 cm to the right of the previously mentioned diverging lens (part A). As a result, the image you found in part (a) is now instead located 42 cm to the right of the converging lens. In other words, once you do the ray tracing diagram from PART A, the object's image is formed. Wherever that image is formed (after the rays meet), the image's location is 42 cm to the right of the converging lens (PART B). On drawing of the situation, there will now be two lens. The image formed from lens 1 is 42 cm to the right of lens 2.
ex:
object ------ image ---- diverging lens ---- converging lens
image is 42 cm to the right of converging lens.
c) Find di and do for the converging lens. What is the "object" in this case? (It will help to add this lens to the drawing in part a)
d) Find the focal length of the converging lens.
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Thank you!
Part A: A diverging lens has of focal length of 15.0 cm. An object is placed...
Part A: A diverging lens has of focal length of 15.0 cm. An object is placed 21 cm to the left of the lens. a) draw a ray diagram showing the situation. b) find the location of the image produced by the lens (mind the signs). Part B: A converging lens is located 30 cm to the right of the previously mentioned diverging lens (part A). As a result, the image you found in part (a) is now instead located...
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