Question

An object is 6.0 cm in front of a converging lens with a focal length of 10 cm

An object is 6.0 cm in front of a converging lens with a focal length of 10cm.
1. Use ray tracing to determine the location of the image.

An object is 32 cm in front of a diverging lens with a focal length of 16 cm.
2. Use ray tracing to determine the location of the image.
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Answer #1
(a)object distance = U = 6 cmfocal length = F = 10 cmimage distance = V = ?by the lens maker's formulawe have1/F = 1/U + 1/V1/V = 1/F - 1/U= 1/10 - 1/6 =V = - 15 cmsince ,image due to converging laens is theinverted - ve signappears in theans :(b)object distance = U =32 cmfocal length = F = 16 cmimage distance = V = ?by the lens maker's formulawe have1/F = 1/U + 1/V1/V = 1/F - 1/U= 1/16 - 1/32V =+ 16 cm+ve signindicates the image is virtual not inveted
answered by: TaKayla
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Answer #2
1) The image distance is1/f = 1/p + 1/q1/(10 cm) =1/(6.0 cm) + 1/qq = 15 cm2) The image distance is1/f = 1/p + 1/q1/(32 cm) =1/(16.0 cm) + 1/qq = 32cm
answered by: MSM
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