a] Let the acceleration be a and tension in string be T.
By force equation, mg -T =ma
and by torque equation, TR = I*alpha
or T = I*alpha/R = mr^2*a/r^2 = ma
adding both equation , mg = 2ma
a = g/2 = - 4.9 m/s^2 answer
b] using third equation of motion,
v = sqrt(2as)
= sqrt(2*4.9*1)
= 3.13 m/s answer
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