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Use the worked example above to help you solve this problem. A solid, frictionless cylinder reel of mass M 2.60 kg and radius
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Answer #1

a] Let the acceleration be a and tension in string be T.

By force equation, mg -T =ma

and by torque equation, TR = I*alpha

or T = I*alpha/R = mr^2*a/r^2 = ma

adding both equation , mg = 2ma

a = g/2 = - 4.9 m/s^2 answer

b] using third equation of motion,

v = sqrt(2as)

= sqrt(2*4.9*1)

= 3.13 m/s answer

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