A proton orbits just at the surface of a charged sphere of radius 0.74 cm. If...

Question

Question

A proton orbits just at the surface of a charged sphere of radius 0.74 cm. If the speed of the proton is 3.55 X109 m/s, what is charge on the sphere?

Answer 1

Answer #1

Solution)

We know,

F = mv^2/r

F = (1.67 x 10^-27 kg)*(3.55x10^5)^2/.0074= 2.844x10^-14J

Now, we also know

F = kq1q2/r2 , so equating the two forces

2.844 x 10^-14J = (9x10^9)(1.602x10^-19)(q2)/.0074^2

q2 = 1.08 x 10^-9 C (Ans)

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Good luck!:)

Answer 2

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