a)
total number of balls = 2+3+4 = 9
total number of arrangement = 9!/(2!*3! * 4!) = 1260
number of arrangement such that all white balls are in a
row
make all white balls as 1 (X)
X, RR,BBBB
hence number of arrangement = 8!/(2! * 4!) = 840
hence required probability = 840/1260
= 2/3
b)
both ends are blue
hence remaing 6 balls RR,BB,WWW
= 7!/(2! *2! * 3!) = 210
required probbaility = 210/1260
= 1/6
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