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A bag contains 4 white, 5 red and 6 blue balls. Three balls are randomly drawn,...

A bag contains 4 white, 5 red and 6 blue balls. Three balls are randomly drawn, without replacement, from the bag. What is the probability that the first two balls are red and the last one is blue?   

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Answer #1

Total no of balls in the bag= 4 white+ 5red + 6 blue= 15 balls

Out of 15 balls 3 balls are selected randomly in 15C3 ways = 455

To find probability that first two balls are red and last one is blue...

Out of 5 red balls 2 balls can be selected in 5C2 ways= 10 ways

And out of 6 blue balls one ball is selected in 6C1 ways= 6 ways.

Required Probability= 5C2 * 6C1 / 15C3 = 0.1319

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