A bag contains 4 white, 5 red and 6 blue balls. Three balls are randomly drawn, without replacement, from the bag. What is the probability that the first two balls are red and the last one is blue?
Total no of balls in the bag= 4 white+ 5red + 6 blue= 15 balls
Out of 15 balls 3 balls are selected randomly in 15C3 ways = 455
To find probability that first two balls are red and last one is blue...
Out of 5 red balls 2 balls can be selected in 5C2 ways= 10 ways
And out of 6 blue balls one ball is selected in 6C1 ways= 6 ways.
Required Probability= 5C2 * 6C1 / 15C3 = 0.1319
A bag contains 4 white, 5 red and 6 blue balls. Three balls are randomly drawn,...
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Please ignore the section discussing the 3 diagrams.
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