Question

4.2pt] Calculate, using Newton's law of gravity, the magnitude of the force of attraction between the Moon and a mass of 33.000 kg on the Earth's surface nearest the Moon The distance to the Moon from surface of the Farth is 376.000 kr. The masomocnis 7.36 10.ke. Gravitational constant G=6.57 x 10 m eg? r Last Answer: 1.14 x 10N Answers Su Not yet correct, tries 2/20 Hint: The Si wywiem of units uses metres as the unit of length. You must change the distance from km tom 3. 12pt] The small spherical planet alled Global of 7500 kg and radius of 6.30x10m). A 32.0 kg satellite is in a circular orbit around the planet steht of 10x10 m above the plane's surface the speed of the satellite Answer S L ast Answer: 59.74 ty r e , tries 2/20
need help with 4 and 5!!!

Answer 1

Ang. 4 given, me mais of moon = 7.36x10 kg Ma" mars of the another object - 83,000 19 distance = 346,000 km d=376,000,000 m G = 6.67X16 Nm / kpl So force in F = GM, Ma = 6,67X10 X7-36 X10 X33000 d² (376,000,00072 F = 1620009.6X10 376X375 X 1012 f = 1.14 N Ans.s - m = 7.50x10 m = 7.500 10 kg Radius = 6.3 heigh tabore sueface is n=1.40x105 m.

Page No. Date d = Reth = 6: 30 x 104 + 1.40 x 10 r = 6.30 x 10+14 x 10 x = 20.30 x109 m so speed of the satellite is v= Gm va 6.67 X1D X7 50X108 - 20:30 X104 V= 2.4643X103 V= / 2464.3 m/s v = 49.64 m/s 2464.3
Thank you