Question

I just understand how to get to the answers of these questions. Please help with all of them. Especially with the reactions

33 Determine the oxidation number of the underlined element in each of the following chemical formulas. Your answers must include any calculations and/or reasoning in how you derived the oxidation numbers. (4 marks total) а) О, b) Н.РО, с) MnO; d) C0 (5 marks total) 34. Identify the element oxidized and the element reduced, in this chemical equation: НASO, + H,S -> HJASO, + S + H,0 (2 marks) a) b) Identify the oxidizing agent and the reducing agent. (2 marks) c) Justify why this is a redox reaction. (1 mark) 35 Balance the following redox equation, using half-reactions. All steps must be shown in your solutions for full marks to be earned. Assume that the reaction occurs in an aqueous solution. (6 marks) Cr NO3 Cr,0,2 NO - Small pieces of silver, copper, and magnesium are placed in solutions that contain one of the following ions: Ag', Cu2*, and Mg2*. The metal/solution combinations tested are summarized in the following table. Any reaction that occurred followed the pattern 36. Мо + Bo) - Bо + M', (aq) where M is a general metal and B is a general metal ion. (аq) Here is the summary of the observations: Cu2+ Mg Ag* Ag No reaction No reaction No reaction Cu Reaction No reaction No reaction Reaction No reaction Mg Reaction In a column, list the oxidizing agents (those being reduced), with the SOA (strongest oxidizing agent) at the top. In a second column, list the reducing agents (those being oxidized), with the SRA (strongest reducing agent) at the bottom. Label the SOA and the SRA. (4 marks)

Answer 1

33. @ Og – oxygen is in triato mie form. so, oxidation state of o' is o same as o [ox state o] 6. H Poy ů Doy 31 462) 3+2 +41-220 3+2- 820 & 9-520 KR . 12+5. o MnO 3 tot 4+3(-2) 2-1 1-6:01 12-176 2 yats 21 y(-2) 27 +4(-2)= -2 24-8=-2 212- 216 42 6 2 122 3. HASO + HS HLASO+S+HO Astré As a reduction +3 o oxidah ده د ع2 - سامی . 4 AsOy is oxidizing agent ts is reducing agent Here, one element is reduced (As) and one element is oxidized (5) that is why this is called red-ox reaction.