A solution is prepared by mixing 1.000 mole of methanol (CH3OH) and 1.37 mole of propanol...
What is the composition of a methanol (CH3OH) – propanol (CH3CH2CH2OH) solution that has a vapor pressure of 187 torr at 40°C? At 40°C, the vapor pressures of pure methanol and pure propanol are 303 and 44.6 torr, respectively. Assume the solution is ideal. Mole fraction of methanol = Mole fraction of propanol =
What is the composition of a methanol (CH3OH) – propanol (CH3CH2OH) solution that has a vapor pressure of 126 torr at 40°C? At 40°C, the vapor pressures of pure methanol and pure propanol are 303 and 44.6 torr, respectively. Assume the solution is ideal. Mole fraction of methanol = Mole fraction of propanol =
A solution is prepared by mixing 44.0 g of acetone (C3H6O) and 297.2g of chloroform (CHCl3). The vapor pressures of pure acetone and pure chloroform at 35 degrees C are 345 and 293 torr. If this is an ideal solution, what is the vapor pressure, in torr, of the solution at 35 degrees C?
A solution is made by mixing 17. g of methanol (CH3OH) and 140. g of acetone ((CH3),co). Calculate the mole fraction of methanol in this solution. Be sure your answer has the correct number of significant digits. x 6 ?
A solution is prepared by dissolving 20.2 mLmL of methanol (CH3OH)(CH3OH) in 100.0 mLmL of water at 25 ∘C∘C. The final volume of the solution is 118 mLmL. The densities of methanol and water at this temperature are 0.782 g/mLg/mL and 1.00 g/mLg/mL, respectively. For this solution, calculate each of the following. a. Molarity b. Molality C. Percent by mass d. Mole Fraction
4) 440 pnts) A solution is prepared by mixing some volume of methanol (MM = 32.04 g/mol, d=0.792 g/mL, p = 94.0 torr) and acetone (MM=58.07 g/mol, d=0.784 g/mL, Pº = 240. torr) at room temperature. Assuming that the volumes additive on mixing. a) What is the mole fraction of acetone and methanol in solution if the number of acetone and methanol gas molecules above the solution are equal to one another? Assume ideal solution behavior.
A solution is prepared by dissolving 20.2 mL of methanol (CH3OH) in 100.0 mL of water at 25 ∘C. The final volume of the solution is 118 mL. The densities of methanol and water at this temperature are 0.782 g/mL and 1.00 g/mL, respectively. For this solution, calculate mole percent M=4.18 m=4.93 percent by mass= 13.6% mole fraction= 8.15*10^-2
I understand how to get 8 but i am stuck on how to find the mole fraction above the solution 8.Find the vapor pressure at 25 °C of a solution in which the mole fractions of benzene and toluene are equal. The vapor pressures at 25 °C of pure benzene and toluene are 72.5 Torr and 26.7 Torr, respectively. 9. Find the mole fraction of each component of the vapor above the solution in exercise 8
5. Ethanol and methanol are form an ideal solution at 20 °C. Vapor pressure of pure ethanol and pure methanol at 20 °C is 44.5 and 88.7 mmHg, respectively. If 100 g of ethanol and 100 g of methanol are mixed into a solution, calculate: (a) the mol fractions of ethanol and methanol in the solution, (b) the partial pressures of ethanol and methanol and total pressure of the solution, and (c) the mol fraction of methanol in a vapor...
Toluene and pyridine form ideal solutions. Consider solution of toluene and pyridine prepared at 25°C. Assuming that the mole fractions of toluene and pyridine in the vapor phase are equal, calculate the composition of the solution. At 25°C the vapor pressures of toluene and pyridine are 28 and 21 torr, respectively. X 42.8 Xtoluene 0.428 Xpyridine