Question

The specific heat c is the amount of heat necessary to change the temperature of 1.00 kg of mass by 1.00°C. The specific heat c is a property of the substance; its Sl unit is J/(kg · K) or J/(kg.°C). Recall that the temperature change (AT) is the same in units of kelvin and degrees Celsius. water silver copper cup Case 1: A 0.780-kg silver pellet with a temperature of 85 °C is added to 0.150 kg of water in a copper cup of unknown mass. The initial temperature of the water and the copper cup is 14 °C. The equilibrium temperature of the system (silver+Water+copper cup) is measured to be 24.5 °C. Assume no heat is exchanged with the surroundings. The specific heats of silver, water and copper are: 234 J/(kg °C), 4186 J/(kg °C) and 387 J/(kg °C), respectively.

Answer 1

mass of silver pellet m, = 0.780 kg Temperature . j = 85% mass of water ma = 0.150 kg Cup mg = ? Temperature of (cup & water) Tq = 14°C - Equilibrium temperature T = 24.8°C specific heat capacity of silver C, = 234J/kg'c water co= 4186J/kg C Copper Cz = 3875/lege (a) heat is released by silver pellet, heat released a = mc (Ti-T) . , = 0.780 X 234 (85–24.5) J 0, = 11042.465) (6) Heat aboobed by water Q₂ = M₂ Cz (T-T2) Q2 = 0.150x4186(24.5–14) J .Q2 = 6592.955] (c) Heat absorbed by copper up is Q3 -,-de = (11042.46–6592-95)J - Q = 4449.51 J Hence for Copper Cup Q₂ = Mg G(T-T2) 4449.51 = M3 X 387 (24.5-14) mg = wong song = 1.095kg