Question

Temperature Change and Heat Capacity - Calorimetry- Two substances The quantitative relationship between heat transfer and temperature change is Q = mcAT, where Q is heat transfer, m is the mass of the substance, and AT is the change in temperature. The symbol c stands for specific heat and depends on the material and phase. The specific heat c is the amount of heat necessary to change the temperature of 1.00 kg of mass by 1.00°C. The specific heat c is a property of the substance; its Sl unit is J/(kg. K) or J/(kg.°C). Recall that the temperature change (AT) is the same in units of kelvin and degrees Celsius. water Aluminum cup Case 1: (a) As shown in the above picture, an unknown amount of water (specific heat = 4186J/(kg °C)) at 32°C is poured into a 0.21-kg aluminum cup (specific heat = 900 J/(kg °C)) with an initial temperature of 15°C. After thermal equilibrium is established, the final temprature of the system (water + cup) is measured to be 26.0 °C.
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Answer 1

sal - Given Herit homister temperature change. Q = M-C.AT & Aluminium Mast of Alluminium, MAR = 0.2 kg Cal = gooj/kg- & 104. - 15 cup The final temperature of Aluminium cup and water systein aftes equilibrium is 'TE. k = 20.0 % Let man of water, = mw - Tw: = 32°C . Cw = 4186J/kg.C Terhath Twi> Tali is heat will be released by water and absorbed by Aluminium cup, Q = MAX CAN (OTAN -0.21% goo x(26-15) 6 = 2079.00f| Ta=20790005 Now,

(6) No heat interaction with surrounding & Heat absorbed by = Heat releated by . Aluminium cup water of 2079 = Mwx Cwx (OT) =) mw X4 186 x (32-26) = 2079 mw = 0.08278.6g wh |MW =0.0828 lei Gie-2;- Given, center, Mas=0.0210kg , Cw=4186 5/kg-°C & Twi= 32°C Alurutisenban That 0.21 kg. Cele = 900 (1y="c Ti = 15°C The heat release to be peritive, it can be wratten, 10 = Meu Com (Tus - To)) The heat absorbed to be poritive, it can be ustetten ass, Q = MAI CAI (Tp - TAL fon, To find Find tempor (If) of system muta (32-T ) = mu ne Ti-Ti ) : 0.0214.41861 32-70) = 0.21x gooult- TE 20:34 C] -20.40"] yil 1659- 29.883