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PELIS JL 4 ELL Prol. UTVU 95. A solution of sodium oxalate (Na-C0A) in acidic solution is titrated with a solution of po (KMn
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Answer #1

95) Moles of Na2C2O4 = mass/molar mass

= 0.119/134 = 0.000888 moles

According to the reaction,

5 mole Na2C2O4 require 2 mole KMnO4

0.000888 mole Na2C2O4 require 2×0.000888/5 mole KMnO4

= 0.000355 moles

Volume of KMnO4 = moles×1000/molarity

= 0.000355×1000/0.0203

= 17.4 ml

Answer is c)

96) Using,

M1V1 (acid) = M2V2 (NaOH)

M1 = 20×0.0521/37.57

= 0.0277 M

Answer is E)

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