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A low-pass filter consists of a 111 Fcapacitor in series with a 158 resistor. The circuit is driven by an AC source with a pe

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Answer? A) cross over when VR=ve frequency IR = 3 wo =) w = I so fo I R = 1 108x9.079 X100Hz = 9.079 410 H₂ = 9,07912 To STRCVe= Ilc 10.0118 ) x (316.01) - 3.728 v Answers c) when f= fc a = √ R² + X2 z = √( 15852 + Xc2 and x = 1 2afcc X = 100 279.079use the above fomulae

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