Question

HW5 Continuous and Normal Random Variables Part1: Problen Previous Problen Problem Lst Next Problem (1 point) The extract ofja plant native to Tawan has been tested as a possible treatment for Leukemia One of the chemical compounds produced from the plant was analyzed for a particular collage deviation of 9.5 grams per mililiter n. The collagen amount was tound to be normally distributed with a mean of 76 and standard (a) What is the probability that the amount of collagen is greater than 74 grams per miter? answer (b) What is the probability that the amount of collagen is less than 80 grams per millter? answer (c) What percentage of compounds formed from the extract of this plant fall witnin 1 standard deviations of the mean? answer

Answer 1

mean = 76 , sd = 9.5

Z = (X - mean)/sd

a)
P(X > 74)
= P (Z> −0.21)
=0.5832

b)
P(X < 80)
= P (Z<0.42)
=0.6628

c)
P(-1 < Z < 1) = 0.6826

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