Solution:
Given: The distance travelled on 1 gallon of fuel is Normally distributed with a mean of 55 miles and a standard deviation of 7 miles.
That is: Mean = and Standard Deviation =
Part A) Find :P( X > 62 ) = ......?
Find z score for x = 62:
z score formula:
Thus we get:
P( X > 62 ) = P( Z > 1.00)
P( X > 62 ) = 1 - P( Z < 1.00)
Look in z table for z = 1.0 and 0.00 and find corresponding Area.
Thus from z table we get: P( Z < 1.00) = 0.8413
Thus
P( X > 62 ) = 1 - P( Z < 1.00)
P( X > 62 ) = 1 - 0.8413
P( X > 62 ) = 0.1587
Part B) Find : P( X < 47) = ........?
Find z score for x = 47
Thus we get:
P( X < 47) = P( Z < -1.14)
Look in z table for z = -1.1 and 0.04 and find area.
Thus from z table, we get:
P( Z < -1.14) = 0.1271
Thus
P( X < 47) = P( Z < -1.14)
P( X < 47) = 0.1271
Part C) Find: P( 50 < X < 59) = .........?
Find z scores for x = 50 and x = 59
P( 50 < X < 59) = P( -0.71 < Z < 0.57)
P( 50 < X < 59) = P( Z < 0.57) - P( Z < -0.71)
Look in z table , for z = 0.5 and 0.07 as well as for z = -0.7 and 0.01 and find area.
Thus from z table , we get:
P( Z < 0.57) = 0.7157 and P( Z < -0.71) = 0.2389
Thus we get:
P( 50 < X < 59) = P( Z < 0.57) - P( Z < -0.71)
P( 50 < X < 59) = 0.7157 - 0.2389
P( 50 < X < 59) = 0.4768
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