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How to solve #3 using energy
I have two equal horizontal springs attached to each other...
3) I have two equal horizontal springs attached to each other on one end. The other...
3) I have two equal horizontal springs attached to each other on one end. The other ends of the spring are fixed (they do not move). The equilibrium length of each spring is 30 cm. I hang a 5 kg mass between the two springs (so that each of the springs now angles downward). The mass drops a distance of 10 cm before stopping. What is the spring constant?
Use energy to solve this. And the answer for k is almost5000 I have two equal...
Use energy to solve this. And the answer for k is almost5000
I have two equal horizontal springs attached to each other on one end. The other ends of the spring are fixed (they do not move). The equilibrium length of each spring is 30 cm. I hang a 5 kg mass between the two springs (so that each of the springs now angles downward). The mass drops a distance of 10 cm before stopping. What is the spring constant...
Use energy to solve this. The answer for k is approximately 4900 I have two equal...
Use energy to solve this. The answer for k is approximately
4900
I have two equal horizontal springs attached to each other on one end. The other ends of the spring are fixed (they do not move). The equilibrium length of each spring is 30 cm. I hang a 5 kg mass between the two springs (so that each of the springs now angles downward). The mass drops a distance of 10 cm before stopping. What is the spring constant...
A massless rod with length L is attached to two springs at its two masses (both...
A massless rod with length L is
attached to two springs at its two masses (both m) at its two ends.
The masses are connected to springs. The springs can move in the
horizontal and vertical directions as shown in the figure and they
both have a stiffness k. Note that gravity acts. Assume the springs
are un-stretched when the rod is vertical. Find the equation of
motion for the system using 1. Newton’s second law 2. Conservation
of energy....
A particle P of mass m kg is attached to two fixed points A and B by two identical model springs,...
A particle P of mass m kg is attached to two fixed points A and B by two identical model springs, each of stiffness k and natural length lo- The point A is at a height 1/o above the point B. The particle is free to oscillate vertically under gravity. The stiffness of each spring is given by k = 4mg/10. The horizontal level passing through the fixed point A is taken as the datum for the gravitational potential energy....
I need the answers for # 5 and #8 2) m m mi Now, three masses...
I need the answers for # 5 and #8
2) m m mi Now, three masses m, = 4.8 kg, m2 = 14.4 kg and m2 = 9.6 kg hang from three identical springs in a motionless elevator. The springs all have the same spring constant that you just calculated above. What is the force the top spring exerts on the top mass? 282.64 N Submit + 3) What is the distance the lower spring is stretched from its equilibrium...
Two identical springs of equilibrium length L and spring stiffness k are attached to opposite sides...
Two identical springs of equilibrium length L and spring stiffness k are attached to opposite sides of a block of mass M totwo parallel walls a distance 2D from each other, where D < L. At what positions will the block be stable?
number 6 solve Two springs with spring constants k_1 and k_2, are connected with each other...
number 6 solve
Two springs with spring constants k_1 and k_2, are connected with each other and attached to a block with mass m, as shown in Figure below.
I need answers for #5 and #7 2) m m2 ma Now, three masses (m, =...
I need answers for #5 and #7
2) m m2 ma Now, three masses (m, = 4.4 kg, m2 = 13.2 kg and mz = 8.8) hang from three identical springs in a motionless elevator. The springs all have the same spring constant given above. What is the magnitude of the force the bottom spring exerts on the lower mass? 86.24 N Submit + 3) What is the distance the middle spring is stretched from its equilibrium length? 79.85 cm...
A single mass m1 = 3.5 kg hangs from a spring in a motionless elevator. The...
A single mass m1 = 3.5 kg hangs from a spring in a motionless elevator. The spring is extended x = 15 cm from its unstretched length. 1) What is the spring constant of the spring? Now, three masses m1 = 3.5 kg, m2 = 10.5 kg and m3 = 7 kg hang from three identical springs in a motionless elevator. The springs all have the same spring constant that you just calculated above. What is the force the top...
3) I have two equal horizontal springs attached to each other on one end. The other ends of the spring are fixed (they do not move). The equilibrium length of each spring is 30 cm. I hang a 5 kg mass between the two springs (so that each of the springs now angles downward). The mass drops a distance of 10 cm before stopping. What is the spring constant?
Use energy to solve this. And the answer for k is almost5000
I have two equal horizontal springs attached to each other on one end. The other ends of the spring are fixed (they do not move). The equilibrium length of each spring is 30 cm. I hang a 5 kg mass between the two springs (so that each of the springs now angles downward). The mass drops a distance of 10 cm before stopping. What is the spring constant...
Use energy to solve this. The answer for k is approximately
4900
I have two equal horizontal springs attached to each other on one end. The other ends of the spring are fixed (they do not move). The equilibrium length of each spring is 30 cm. I hang a 5 kg mass between the two springs (so that each of the springs now angles downward). The mass drops a distance of 10 cm before stopping. What is the spring constant...
A massless rod with length L is
attached to two springs at its two masses (both m) at its two ends.
The masses are connected to springs. The springs can move in the
horizontal and vertical directions as shown in the figure and they
both have a stiffness k. Note that gravity acts. Assume the springs
are un-stretched when the rod is vertical. Find the equation of
motion for the system using 1. Newton’s second law 2. Conservation
of energy....
A particle P of mass m kg is attached to two fixed points A and B by two identical model springs, each of stiffness k and natural length lo- The point A is at a height 1/o above the point B. The particle is free to oscillate vertically under gravity. The stiffness of each spring is given by k = 4mg/10. The horizontal level passing through the fixed point A is taken as the datum for the gravitational potential energy....
I need the answers for # 5 and #8
2) m m mi Now, three masses m, = 4.8 kg, m2 = 14.4 kg and m2 = 9.6 kg hang from three identical springs in a motionless elevator. The springs all have the same spring constant that you just calculated above. What is the force the top spring exerts on the top mass? 282.64 N Submit + 3) What is the distance the lower spring is stretched from its equilibrium...
number 6 solve
Two springs with spring constants k_1 and k_2, are connected with each other and attached to a block with mass m, as shown in Figure below.
I need answers for #5 and #7
2) m m2 ma Now, three masses (m, = 4.4 kg, m2 = 13.2 kg and mz = 8.8) hang from three identical springs in a motionless elevator. The springs all have the same spring constant given above. What is the magnitude of the force the bottom spring exerts on the lower mass? 86.24 N Submit + 3) What is the distance the middle spring is stretched from its equilibrium length? 79.85 cm...
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