Two point charges, q1 = 100 nC and q2 = −60 nC, are held 15.0 cm...
Two point charges, q1 = 100 nC and q2 = −60 nC, are held 15.0 cm apart. What is the electric field at a point 5.0 cm from the negative charge and along the line between the two charges?
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A. 278 kN/C
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B. 351 kN/C
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C. 306 kN/C
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D. 323 kN/C
Homework Answers
Electric field at given point is given by
E = k ( q1/ r1^2 + q2 / r2^2)
E = 9*10^9* 10^-9* ( 100/ 0.1^2 + 60/ 0.05^2)
E = 306 kN/C
Comment in case any doubt please rate my answer ....
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