part A)
let the angle of the ramp is theta
Using conservation of energy
0.50 * m * v^2 = m * g * L * sin(phi)
0.50 * 2.93^2 = 9.8 * 1.57 * sin(phi)
solving for phi
phi = 16.2 degree
the angle between the ramp and horizontal is 16.2 dgeree
part B)
let the velocity is v
Using work energy theorem
0.50 * 9 * v^2 = 9 * 9.8 * 1.57 * sin(16.2 degree) - 11 * 1.57
solving for v
v = 2.18 m/s
the speed at the bottom is 2.18 m/s
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