Question

100 days 17 Question 1 An antique Roman coin twice. The tree diagram below shows the probabilities of the different outcomes. is biased towards tails due to a heavy decoration stamped on the back. The unfair coin is flipped 5 3 ok Pro

Answer 1

Here we want to find P( 1 head and 1 tail )

There are two possible ways as

P(head on first toss) * P( tail on second toss | head on first toss) = (1/6)*(5/6) = 5/36

and P(tail on first toss) * P( head on second toss | tail on first toss) = (5/6)*(1/6) = 5/36

Therefore required probability = (5/36)+(5/36) = 10/36 = 5/18  (This is the final answer).