Question

O KINETICS AND EQUILIBRIUM Using the Arrhenius equation to calculate Ea from k versus T data The rate constant k for a certai
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Talidst L NU According to Arrhenius equation, K & K Rate constant at temperature Tz 4T, Ea - Activation energy. R → Gas ConstT2=148°C k=3.3x109 T = 89°C =89+273K 362K = 148+273K k=5.7x109 421k In 15.78 104 = Ea 1421-362 1 (3.3x109 / 8.314 I 421x362)1 kJ = 1000 J

Add a comment
Know the answer?
Add Answer to:
O KINETICS AND EQUILIBRIUM Using the Arrhenius equation to calculate Ea from k versus T data...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • KINETICS AND EQUILIBRIUM Using the Arrhenius equation to calculate Ea from k versus T data The...

    KINETICS AND EQUILIBRIUM Using the Arrhenius equation to calculate Ea from k versus T data The rate constant k for a certain reaction is measured at two different temperatures: temperaturek 204.0 °C | 2.4 × 1010 333.0 °c 5.7 x 101 Assuming the rate constant obeys the Arhenius equation, calculate the activation energy Ea for this reaction. Round your answer to 2 significant digits. IP mol

  • O KINETICS AND EQUILIBRIUM Using the Arrhenius equation to calculate Ea from k versus T data...

    O KINETICS AND EQUILIBRIUM Using the Arrhenius equation to calculate Ea from k versus T data The rate constant k for a certain reaction is measured at two different temperatures: temperature k 3.4x 101 172.0 C 1.1 x 1012 242.0 °C Assuming the rate constant obeys the Arrhenius equation, calculate the activation energy E, for this reaction. Round your answer to 2 significant digits. kJ E= mol

  • KINETICS AND EQUILIBRIUM Using the Arrhenius equation to calculate k at one temperatur... The rate constant...

    KINETICS AND EQUILIBRIUM Using the Arrhenius equation to calculate k at one temperatur... The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy E.=23.0 kJ/mol. If the rate constant of the reaction is 1.2 x 10' M 's at 136.0 °C, what will the rate constant be at 230.0 °C? Round your answer to 2 significant digits. - M .,

  • The rate constant k for a certain reaction is measured at two different temperatures: temperature 148.0°C...

    The rate constant k for a certain reaction is measured at two different temperatures: temperature 148.0°C 78.0°C k 9.7x10? 9.4 x 10° Assuming the rate constant obeys the Arrhenius equation, calculate the activation energy E for this reaction. Round your answer to 2 significant digits. 9.- Omol

  • O KINETICS AND EQUILIBRIUM Using a second order integrated rato low to find concentration '. At...

    O KINETICS AND EQUILIBRIUM Using a second order integrated rato low to find concentration '. At a certain temperature this reaction follows second-order kinetics with a rate constant of 13.1 M 250,() 250,()+0,6) Suppose a vessel contains so, at a concentration of 0.130 M. Calculate the concentration of SO, in the vessel 9.20 seconds later. You may assume no other reaction is important Round your answer to 2 significant digits. O KINETICS AND EQUILIRIUM Using the Arrhenius equation to calculate...

  • The rate constant k for a certain reaction is measured at two different temperatures: temperature 397.0°C...

    The rate constant k for a certain reaction is measured at two different temperatures: temperature 397.0°C 280.0°C k 1.1 x 1010 1.3 x 10° Assuming the rate constant obeys the Arrhenius equation, calculate the activation energy for this reaction. Round your answer to 2 significant digits. 0.

  • The Arrhenius equation shows the relationship between the rate constant k and the temperature T in...

    The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k=Ae−Ea/RT where R is the gas constant (8.314 J/mol⋅K), A is a constant called the frequency factor, and Ea is the activation energy for the reaction. However, a more practical form of this equation is lnk2k1=EaR(1T1−1T2) which is mathmatically equivalent to lnk1k2=EaR(1T2−1T1) where k1 and k2 are the rate constants for a single reaction at two different absolute...

  • The Arrhenius equation shows the relationship between the rate constant k and the temperature T in...

    The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k=Ae−Ea/RT where R is the gas constant (8.314 J/mol⋅K), A is a constant called the frequency factor, and Ea is the activation energy for the reaction. However, a more practical form of this equation is lnk2k1=EaR(1T1−1T2) which is mathmatically equivalent to lnk1k2=EaR(1T2−1T1) where k1 and k2 are the rate constants for a single reaction at two different absolute...

  • The Arrhenius equation shows the relationship between the rate constant k and the temperature T in...

    The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k=Ae−Ea/RT where R is the gas constant (8.314 J/mol⋅K), A is a constant called the frequency factor, and Ea is the activation energy for the reaction. However, a more practical form of this equation is lnk2k1=EaR(1T1−1T2) which is mathmatically equivalent to lnk1k2=EaR(1T2−1T1) where k1 and k2 are the rate constants for a single reaction at two different absolute...

  • Learning Goal: To use the Arrhenius equation to calculate the activation energy. As temperature rises, the...

    Learning Goal: To use the Arrhenius equation to calculate the activation energy. As temperature rises, the average kinetic energy of molecules increases. In a chemical reaction, this means that a higher percentage of the molecules possess the required activation energy, and the reaction goes faster. This relationship is shown by the Arrhenius equation k=Ae−Ea/RT where k is the rate constant, A is the frequency factor, Ea is the activation energy, R = 8.3145 J/(K⋅mol) is the gas constant, and T...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT